設z1=m2+1+(m2+m-2)i,z2=4m+2+(m2-5m+4)i,若z1<z2,求實數m的取值...
問題詳情:設z1=m2+1+(m2+m-2)i,z2=4m+2+(m2-5m+4)i,若z1<z2,求實數m的取值範圍.【回答】[解]由於z1<z2,m∈R,∴z1∈R且z2∈R,當z1∈R時,m2+m-2=0,m=1或m=-2.當z2∈R時,m2-5m+4=0,m=1或m=4,∴當m=1時,z1=2,z2=6,滿足z1<z2.∴z1<z2時,實數m的取值爲m=1.知識點:數系...