x32ax23xa0的精选

问题详情：已知函数f(x)=-x3+2ax2+3x(a>0)的导数f′(x)的最大值为5,则在函数f(x)图象上的点(1,f(1))处的切线方程是()A.3x-15y+4=0         B.15x-3y-2=0C.15x-3y+2=0         D.3x-y+1=0【回答】B....