FOC5的精选

问题详情：如图，已知CD⊥AB，垂足点为O，若∠FOC=5∠COE，求∠AOF的度数？ 【回答】解：∵∠FOC=5∠COE， 而∠FOC+∠COE=180°， ∴5∠COE+∠COE=180°， ∴∠COE=30°， ∴∠DOF=30°， ∵CD⊥AB， ∴∠AOD=90°， ∴∠AOF=∠AOD+∠DOF...