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設函數f(x)=x3-4x+a(0<a<2)有三個零點x1,x2,x3,且x1<x2<...

設函數f(x)=x3-4x+a(0<a<2)有三個零點x1,x2,x3,且x1<x2<...

2022-09-06
問題詳情:設函數f(x)=x3-4x+a(0<a<2)有三個零點x1,x2,x3,且x1<x2<x3,則下列結論正確的是()A.x1>-1               B.x2<0C.x3>2                    D.0<x2<1【回答】D.因為函數f(...