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方程x2+x-12=0的两个根为(  )A.x1=-2,x2=6          B.x1=-6,x2=2 ...

方程x2+x-12=0的两个根为(  )A.x1=-2,x2=6          B.x1=-6,x2=2 ...

2019-02-04
问题详情:方程x2+x-12=0的两个根为()A.x1=-2,x2=6          B.x1=-6,x2=2          C.x1=-3,x2=4          D.x1=-4,x2=3【回答】D【解析】试题分析:将x2+x﹣12分解因式成(x+4)(x﹣3),解x+4=0或x﹣3=0即可得出...
方程的两个根为      (A)x1=-2,x2=6                           (B...

方程的两个根为      (A)x1=-2,x2=6                           (B...

2020-03-25
问题详情:方程的两个根为      (A)x1=-2,x2=6                           (B)x1=-6,x2=2(C)x1=-3,x2=4                           (D)x1=-4,x2=3【回答】D知识点:各...
方程x2﹣4x﹣12=0的解为(  )A.x1=2,x2=6                         ...

方程x2﹣4x﹣12=0的解为(  )A.x1=2,x2=6                         ...

2020-06-21
问题详情:方程x2﹣4x﹣12=0的解为()A.x1=2,x2=6                                         B.x1=2,x2=﹣6 C.x1=﹣2,x2=6                               ...