200克某硫*恰好与26克锌完全反应,试计算: (1)生成*气的质量; (2)硫*溶液中溶质的质量分数; (3...
问题详情:
200克某硫*恰好与26克锌完全反应,试计算:
(1)生成*气的质量;
(2)硫*溶液中溶质的质量分数;
(3)充分反应后所得溶液的质量。
【回答】
设生成H2质量为x,硫*溶液中溶质质量为y
↑ ·····························(1分)
65 98 2
26g y x ·····························(1分)
·····································(1分)
x=0.8g y=39.2g ····································(1分)
w(H2SO4) ························(1分)
反应后所得溶液的质量为:200+26-0.8=225.2g ············(1分)
答:(1)生成H2 0.8克;
(2)硫*溶液中溶质质量分数为19.6%;
(3)反应后溶液质量为225.2克。
知识点:未分类
题型:未分类