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.设直线l1:kx﹣y+1=0,l2:x﹣ky+1=0,若l1∥l2,则k=(  )A.﹣1         ...

.设直线l1:kx﹣y+1=0,l2:x﹣ky+1=0,若l1∥l2,则k=(  )A.﹣1         ...

2019-11-10
问题详情:.设直线l1:kx﹣y+1=0,l2:x﹣ky+1=0,若l1∥l2,则k=()A.﹣1          B.1                         C.±1           D.0【回答】A知识点:直线与方程题型:选择题...