2n01的精选

问题详情：正项数列{an}满足-(2n-1)an-2n=0.(1)求数列{an}的通项公式an.(2)令bn=,求数列{bn}的前n项和Tn.【回答】 (1)由-(2n-1)an-2n=0,得(an-2n)(an+1)=0.由于{an}是正项数列,所以an=2n.(2)由an=2n,bn=,则bn==.所以T...