980kJmol的精选

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常温下，已知:CH4(g)+2O2(g)=CO2(g)+2H2O(1) ∆H=-980kJ/mol 2H2(g...

常温下，已知:CH4(g)+2O2(g)=CO2(g)+2H2O(1) ∆H=-980kJ/mol 2H2(g...

2019-03-20
问题详情：常温下，已知:CH4(g)+2O2(g)=CO2(g)+2H2O(1) ∆H=-980kJ/mol 2H2(g)+O2(g)=2H2O(1) △H=-560kJ/mol现有CH4和H2组成的混合气体共0.4mol,使其在O2中完全燃烧，恢复至常温共放出252kJ的热量，则CH4与H2的物质的量...